32=25x^2-4

Solution for 32=25x^2-4 equation:

32=25x^2-4

We move all terms to the left:

32-(25x^2-4)=0

We get rid of parentheses

-25x^2+4+32=0

We add all the numbers together, and all the variables

-25x^2+36=0

a = -25; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-25)·36
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-25}=\frac{-60}{-50}
=1+1/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-25}=\frac{60}{-50}
=-1+1/5
$